SolveWithPython

You’ll build a frequency dictionary from a string.
This mirrors real parsing and analytics tasks.
Estimated time: 15 minutes | Difficulty: Beginner

Problem

Count how often each character appears in a string.

Inputs

• text: str

Output

Return a dictionary of character counts.

Example

Input

Output

Constraints

• Do not use external libraries
• Input may be empty
• Count all characters exactly as they appear (including spaces and punctuation)
• Case-sensitive: "A" and "a" are different characters

Requirements

• Function name: char_frequency(text: str) -> dict
• Parameter: text (string)
• Return type: dict[str, int]

Edge Cases to Consider

• Empty string
• Repeated characters
• Spaces and punctuation
• Mixed case letters

Explanation

• Iterate over each character and increment a counter in a dictionary
• Time complexity: O(n)
• Space complexity: O(k) where k is the number of unique characters

You can use the following tests above to verify your solution locally.

🔗 View reference solution on GitHub
(After you’ve tried the challenge)

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You’ve completed this challenge. The best way to improve your Python skills is to keep practicing while the concept is fresh.

👉 Next Challenge → Filter Even Numbers

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